Agcl is less soluble in nacl(aq) than in water because
a) of a decrease in na+ ions.
b) agcl forms complex ions with nacl.
c) of a common ion effect.
d) nacl has a higher solubility product.

c) of a common ion effect.

Explanation:

AgCl is an ionic compound

This means that when we dissolve it will dissociate in the elements that compose it.

Now let's assume that we have a certain amount of AgCl that we want to dissolve in NaCl.

We dissolve and observe that there is an amount that precipitates.

This occurs because the solution is supersaturated, it means that more solute has been added than can be dissolved in the solvent.

Now we take the same amount of AgCl and dissolve it in water (the water is at the same temperature as the NaCl) and see that it dissolves completely.

This difference is since when we dissolve AgCl in NaCl it has a common ion, Cl.

When the AgCl dissociates there is already a certain amount of Cl in the solvent and the solution will tolerate less Cl ions (it will saturate faster) than water.

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first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j