The titration of 25.0 ml of an unknown concentration h2so4 solution requires 83.6 ml of 0.12 m lioh solution. what is the concentration of the h2so4 solution (in m)? question 16 options:

2LiOH + H₂SO₄ = Li₂SO₄ + 2H₂O

v(H₂SO₄)=0.025 L
v(LiOH)=0.0836 L
c(LiOH)=0.12 mol/L

n(LiOH)=v(LiOH)c(LiOH)

n(H₂SO₄)=n(LiOH)/2=v(LiOH)c(LiOH)/2

c(H₂SO₄)=n(H₂SO₄)/v(H₂SO₄)=v(LiOH)c(LiOH)/(2v(H₂SO₄))

c(H₂SO₄)=0.0836*0.12/(2*0.025)=0.20064 mol/L

≈0.20 M

Answer (b) supersaturation;