Chemistry, 27.09.2019 06:00, aide1234564

The molar mass of sucrose (c12h22o11) is 342.3 g/mol. a chemist has a 0.500-mol sample of sucrose. what is the mass, in grams, of this sample? 171 342 500 684

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The mass of a chemical compound can be calculated for if its molecular mass and its moles is known. The product of the moles and the molecular mass will the give the mass in gram of that substance.
The appropriate formula for this work is : Mass of sucrose in 0.5mol = Moles * molecular weight
0.5 * 342.3 = 171.15
Thus, the mass in grams of the sample is 171.

answered: happy121906

The mass of the sucrose is 171 g

Solution:

$\text{Number moles}=\frac{\text{Mass of the compound}}{\text{Molecular mass of the compound}}$

The molar mass of sucrose ( $C_{12}H_{22}O_{11}$ ) is 342.3 g/mol

Moles of sucrose = 0.500 moles

Mass of the sucrose :

$\text{Number moles of sucrose}=\frac{\text{Mass of the sucrose}}{\text{Molecular mass of the sucrose}}=$

$\text{Mass of the sucrose}=\text{Number moles of sucrose}\times \text{Molecular mass of the sucrose}=0.500mol\times 342.3g/mol=171.15\approx 171 g$

Hence, the mass of the sucrose is 171 g.

answered: Guest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

answered: Guest

Answer : option c) heat is released during the process.explanation :

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.

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The molar mass of sucrose (c12h22o11) is 342.3 g/mol. a chemist has a 0.500-mol sample of sucrose. w...