The philosopher’s stone weighs 43.2 g is placed in a graduated cylinder containing 63 ml of water. after the stone is added to the cylinder the water rises to 74 ml. what is the density of the stone? express your answer in g/ml.

Explanation:

Hi, when putting the stone in the water it moves a volume of water equal to its own volume. So, if the initial volume in the cylinder is 63 ml and the final is 74 ml, the stone's volume can be calculated as:

Now, you know the weigh and the volume of the philosopher's stone. The definition of density is mass per volume:  

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied