How many grams of ca are needed to react completely with 2.20 l of a 4.50 m hcl solution

There are needed 198g of Ca to react completely with 2.20L of a 4.50M HCl solution

Explanation:

First we need to establish the chemical reaction between Ca and HCl.

Ca + HCl → CaCl₂ + H₂

Then we need to balance the equation to find out the stoichiometry of the reaccion, to do this we need to keep in count that in a chemical reaction mass cannot be generated or created, so the reactants must have the same amount of mass as the product

The balanced equation is:

Ca + 2HCl → CaCl₂ + H₂

This means that 1 mol of Ca reacts with 2 moles of HCl to form 1 mol of CaCl₂ and 1 mol of H₂.

Next we need to find out how many moles we have in the solution.

1L of solution ⇒ 4.50 moles of HCl

2.20L of solution ⇒ x moles of HCl

x = 9.9 moles of HCl

Now we use the stoichiometric ratio between HCl a Ca to find out how many moles react with 9.9 moles of HCl.

2 moles of HCl  ⇒ 1 mol of Ca

9.9 moles of HCl ⇒ x moles of Ca

x = 4.95 moles of Ca

Finally we calculate how many grams 4.95 moles of Ca are, using the Ca molar mass.

1 mol of Ca ⇒ 40g

4.95 moles of Ca ⇒ x g

x = 198g

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.