Asample of nitrogen gas has a pressure of 7.58 kpa at 639 k. what will be the pressure at 311 k if the volume does not change?

3.69 kPa

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

    (At constant volume and number of moles)

where,

= initial pressure of gas = 7.58 kPa

= final pressure of gas = ?

= initial temperature of gas = 639 K

= final temperature of gas = 311 K

Now put all the given values in the above equation, we get the final pressure of gas.

Therefore, the final pressure of gas will be 3.69 kPa.

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