What volume in ml of a 2.9m solution is needed in order to prepare 2.3l of a 1.1m solution?

tell me the equation too .

As i am reading the question, I notice they give two concentrations (M), one volume (L), and they are asking for another volume. this is a hint that you need to use the following formula

C1V1 = C2V2                (note: C stands for concentration)

C1= 2.9 M
V1= ?
C2= 1.1 M
V2= 2.3 L

now let's plug in the numbers

( 2.9 x V1)= (1.1 X 2.3)

V1= 0.87 Liters

1. and 2. question: in which equation? or i don't understand you, 3. a), 4. c), 5. c), 6. b), 7. d), 8. d) if small number is underlined(behind symbol) , b) if big number is underlined(in front of symbol)9. what is underlined there? 10. c)