Consider the reaction.

which statement is true at stp? (the atomic mass of mg is 24.31 u.)
3.0 g of mg produce 3.0 l of h2 gas.
3.0 g of mg produce 22.4 l of h2 gas.
24.31 g of mg produce (3 22.4) l of h2 gas.
(3 24.31) g of mg produce (3 22.4) l of h2 gas.

Answer is: (3 24.31) g of Mg produce (3 22.4) L of H2 gas.

Balanced chemical reaction:

3Mg(s) + 2H₃PO₄(aq) → Mg₃(PO₄)₂(s) + 3H₂(g).

From chemical reaction: n(Mg) : n(H₂) = 3 : 3 (1 : 1).

n(Mg) = n(H₂).

m(Mg) = 24.31 g; mass of magnesium.

n(Mg) = m(Mg) ÷ M(Mg).

n(Mg) = 24.31 g ÷ 24.31 g/mol.

n(Mg) = 1 mol; amount of the magnesium.

V(H₂) = n(H₂) · Vm.

V(H₂) = 1 mol · 22.4 L/mol.

V(H₂) = 22.4 L; volume of the hydrogen gas.

So, 3·24.31 g of magnesium (3 mol) produce 3·22.4 liters of hydrogen.

if the concentration of products is decreased, the equilibrium will shift toward the products). add an inert gas (one that is not involved in the reaction) to the constant-volume reaction mixture: this will increase the total pressure of the system, but will have no effect on the equilibrium condition.

explanation:

practical process described pest part of scientific investigation.

because practical knowledge is powerful then therotical knowledge.