Acontainer with a specific volume “v” changes to “2v.” what happens to the average distance between gas molecules? assume that pressure and temperature of the gas remain constant.

Explanation:

It is given that the volume is changing from V to 2V whereas both pressure and temperature remains the same.

So, this also means that number of moles of the substance remains the same but only change in volume is occurring. Therefore, greater volume of container will lead to more space for the movement of molecules.

As a result, molecules will start to move away from each other. Hence, space between them will increase.

Thus, we can conclude that the average distance between gas molecules will increase.

can you attach a picture of the lettuce? : )

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j