When bismuth-212 undergoes alpha decay, it becomes which of the following?
asatine-208 + an alpha particle
lead-210 + an alpha particle
polonium-210 + and alpha particle
thallium-208 + and alpha particle

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When bismuth-212 undergoes alpha decay, it becomes ²⁰⁸Tl

Explanation: -

Mass number of ²¹²Bi = 212

Atomic number of ²¹²Bi = 83

When alpha decay occurs the mass number decreases by 4 and the atomic number decreases by 2.

Mass number of daughter = 212 - 4 = 208

Atomic number of daughter = 83 - 2 = 81

It is the atomic number of Thallium Tl.

Thus the daughter nucleide is ²⁰⁸Tl.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.

the answer is d. 74.02