An element x belongs to 4th period and 17th group. write the formula of the compound formed when it reacts with y( atomic no.-13, mass no.27.)

All element in group 17th have their oxidation number to be -1 and for the other element its shell configuration should be 2,8,3...therefore its oxidation number should be +3
therefore the formular should be YX3

Hey how did you manage to type such a big lab report

The answer is c) pyrite