What must be true in order for magnetism to induce an electric current in a wire? there needs to be a switch in the circuit. there cannot be a switch in the circuit. the wire must be part of a closed circuit. the wire must be part of an open circuit. mark this and return save and exit

The correct " The wire must be part of a closed circuit."

The three conditions that must be met in odder to have a current flowing in a wire are : The wire has to be a conductor that is  connected in a closed circuit , and you must have an emf to drive the charges in a certain direction in the wire.  A magnet that provides a changing flux will induce an emf that drives current.  When the magnet produces this emf, a current will only flow though the conducting wire if and only if the wire s part of a closed circuit.

Clearly, the correct answer is " The wire must be part of a closed circuit."

the grams   of   barium that   are in   2.3 x 10^23   atoms of barium   is   52.4 g (answer c)

    calculation

mass = moles   of ba   x molar   mass of ba

  molar mass of ba from periodic table=   137.3 g/mol

  use the   avogadro's law   constant   to   calculate the moles of barium

  that   is     1 mole =   6.02   x 10^23 atoms

                    ? moles = 2.3 x 10^23   atoms

by cross   multiplication

=(1 mole   x 2.3x 10^23 atoms)   / 6.02   x10^23 atoms)=   0.382   moles

mass   is therefore = 137.3   g/mol x 0.382 mol = 52.4 ( answer c)

explanation:

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