If 0.600 gram of zinc is used, what is the amount of zinc chloride that is produced in the above reaction?

 The solution would be like this for this specific problem:

Zn + 2HCl --> ZnCl2 + H2 

Molar Mass Zinc - 65.38 g/mol 
Molar Mass Zinc Chloride - 136.38 g/mol 
Number of moles of zinc reacting = 0.600 g / 65.38g/mol = 0.00918 moles 0.00918 moles * 136.38 g/mole = 1.25 g ZnCl2 

Answer = 1.25 grams of zinc chloride

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it is reliable if two scientists recorded it