1mole of nacl is dissolved in a 1000 grams of water and 1 mol cacl2 is dissolved in a second beaker containing 1000 grams of water. which statement is most accurate?

a)the cacl2 beaker has more ions in solution.
b)the nacl solution has more particles dissolved in the water.
c)the cacl2 has a lower boiling point than the nacl solution.
d)the nacl solution has a lower freezing point that the cacl2 solution, eliminate

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.

they are called fossil fuels

it would only be the stuff in module eight so you need to study all the lessons in that you also could check the flvs

hope this : )