Calculate the value of the equilibrium constant, kc, for the reaction below, if 0.208 moles of sulfur dioxide gas, 0.208 moles of oxygen gas and 0.425 moles of sulfur trioxide gas are present in a 1.50-liter reaction vessel at equilibrium.

2so2(g) +o2 (g) < --> 2so3 (g)

a. kc=3.32 x 10^-2
b. kc=2.01 x 10^1 (i know for a fact this one is wrong.)
c. kc=2.98 x 10^1
d. kc=1.47 x 10^1

!

In the following reaction, oxygen is the excess reactant. sicl4 + o2 → sio2 + cl2 the table shows an experimental record for the above reaction. experimental record trial starting amount of sicl4 starting amount of o2 actual yield of sio2 1 120 g 240 g 38.2 g 2 75 g 50 g 25.2 g part 1: calculate the percentage yield for sio2 for trial 1. also, determine the leftover reactant for the trial. show your work. part 2: based on the percentage yield in trial 2, explain what ratio of reactants is more efficient for the given reaction.