When 26.62 miles of fes2 reacts with 5.44 miles of o2 how many miles of so2 are formed

4 parts of FeS2 reacts with 11 parts of O2
so 26,62 moles of FeS2 would need 26,62/4 *11 = 73,2 moles of O2

So only 5,44 /11 *4 = 1,98 moles of FeS2 reacts with 5,44 moles of O2, O2 is the limiting
reactant
This means FeS2 is the reactant in excess and 26,62 - 5,44 = 21,18 moles of FeS2 are left over
and 1,98 * 8/4 = 3,96 moles of SO2 are formed