The ph of a 0.1 m ch3cooh solutions is

Let’s start with our generic acid equilibrium constant equation;

Ka=[H+][A−][HA]Ka=[H+][A−][HA]

Which in our case is

Ka=[H+][CH3COOH−][CH3COOH]Ka=[H+][CH3COOH−][CH3COOH]

We can solve this using an Ice Table

Plugging back into our original equation yields

1.8*10^-^5=\frac{[x][x]}{[.1-x]}1.8*10^-^5=\frac{[x][x]}{[.1-x]}

Solving gives us an X value of 0.00133267. (Just plug it into Wolfram Alpha). Since this value is equal to our [H+][H+] we can take the -log of it, giving a pH of 2.875

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.

the earth would become to overheated and everything alive on it will eventually die from overheating. plants will eventually die as well, water will evaporate, and it will be nothing but a hot planet without anything living on it.