One mole of an ideal gas is sealed in a 22.4-l container at a pressure of 1 atm and a temperature of 273 k. the temperature is then increased to 301 k , but the container does not expand. what will the new pressure be?

Since the container did not expand despite the change, this means that volume was constant during the process. Gay-Lussac's law states that for ideal gases with constant volume, pressure and temperature are directly proportional.

Mathematically, we have



where P₁ & P₂ are the pressures and T₁ & T₂ are the temperatures of the system. 

Using the values provided, we have





Therefore, the new pressure has a value of 1.10 atm.

1.10 atm