What volume of a 6.67 m nacl solution contains 3.12 mol nacl? ?

The volume of a 6.67 m nacl solution that contains 3.12 mol nacl is 0.468.

You just need to follow this formula:

C = n / V

So, it will be

V = n / C

    = 3.12 / 6.67 moles / Liter

     = 0.468 L

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be