Given the reaction: ca + 2h2o → ca(oh)2 + h2 what is the total number of moles of ca needed to react completely with 4.0 moles of h2o?

Since the given equation is balanced, we know the Ca and the H2O are in a 1:2 ratio (to see the ratio, look at the coefficients in front of the molecules). Then, there are a few different ways to solve the problem. I am going to show you how to solve it using a ratio of moles of Ca/moles of H2O: x/1=4/2. First, you cross multiply to get 2x=4. Then, you divide both sides by 2 to get x=2 moles of Ca.

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer