Chemistry, 27.08.2019 20:50, 4004JuCh18

Abase is added to an acid during a titration. a ph meter is used to monitor the reaction’s progress. when should the addition of base stop? when adding a few drops of base causes a large decrease in ph when adding a few drops of base causes a large increase in ph when adding a few milliliters of base causes a large increase in ph when adding a few milliliters of base causes a large decrease in ph

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answered: alexis3060

when adding a few drops of base causes a large increase in pH

answered: genyjoannerubiera

The correct answer is'when adding a few drops of base causes a large increase in pH'.

Explanation:

When an acid reacts with base neutralization reaction occurs which means that H^+ ions from the acid and OH^- ion from the base combine together to form neutral molecule of water.

If the concentration of H^+

is slightly higher than the OH^-

concentration then the pH of the solution will become lower than 7.If the concentration of OH^-

is slightly higher than the H^+

concentration then the pH of the solution will become higher than 7.If concentration of both H^+

and

are equal then the pH of the solution will be 7. That is neutral pH.

During the titration , while adding base to an acid. Addition of base must be stopped when large increase in value of pH of an acid is observed on a pH meter.

answered: Guest

answer; i do believe the correct answer is (river); /// good luck

answered: Guest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

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