You have a stock solution of 14.8 m nh3. how many milliliters of this solution should you dilute to make 100.0 ml of 0.250 m nh3?

To determine the volume needed of the more concentrated solution to dilute it into the desired concentration, we use the equation M1V1 = M2V2 where M1, M2 are concentrations and V1,V2 are volumes.

M1V1 = M2V2
14.8(V1) = (100.0)(0.250)
V1 = 1.69 mL needed

Hope this answers the question.

It shows that the experiment is designed properly.