Chemistry

Chemistry, 23.09.2019 23:50, ashleyremon

In the standardization of the na2s2o3 solution, if you did not titrate the liberated iodine immediately, how would this likely affect the value of the molarity you calculate?

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Chemistry, 11.07.2019 11:30, toriflaherty

Given that it requires 27.9 ml of 0.270 m na2s2o3(aq) to titrate a 15.0-ml sample of i3–(aq), calculate the molarity of i3–(aq) in the solution.

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Chemistry, 25.07.2019 22:20, nataluarenhg6924

The amount of i−3(aq) in a solution can be determined by titration with a solution containing a known concentration of s2o2−3(aq) (thiosulfate ion). the determination is based on the net ionic equation 2s2o2−3(aq)+i3(aq)⟶s4o2−6(aq)+3i−(aq) given that it requires 29.6 ml of 0.260 m na2s2o3(aq) to titrate a 30.0 ml sample of i−3(aq), calculate the molarity of i−3(aq) in the solution.

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Chemistry, 18.10.2019 17:10, Lydiaxqueen

The amount of i−3(aq)i3−(aq) in a solution can be determined by titration with a solution containing a known concentration of s2o2−3(aq)s2o32−(aq) (thiosulfate ion). the determination is based on the net ionic equation 2s2o2−3(aq)+i−3(aq)⟶s4o2−6(aq)+3i−(aq) 2s2o32−(aq)+i3−(aq)⟶s4o62−(aq)+3i−(aq) given that it requires 25.2 ml25.2 ml of 0.470 m na2s2o3(aq)0.470 m na2s2o3(aq) to titrate a 10.0 ml10.0 ml sample of i−3(aq),i3−(aq), calculate the molarity of i−3(aq)i3−(aq) in the solution.

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Chemistry, 19.10.2019 00:30, laequity7325

Sodium thiosulfate, na2s2o3, is used as a fixer in photographic film developing. the amount of na2s2o3 in a solution can be determined by a titration with iodine, i2, according to the equation: 2na2s2o3(aq) + i2(aq) --> na2s4o6 +2nai(aq). calculate the concentration of the na2s2o3 solution if 23.50 ml of a 0.1710 m i2 solution react exactly with a 100.0 ml sample of the na2s2o3 solution. use 4 sig. fig. aside, the end of the titration is determined by the color. nai is a pale yellow and i2 is a deep purple. just when the purple color persists, all the iodine that can react has reacted.

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