What is the molarity of a hcl solution that contains 8.53 g of hcl in 372 ml of solution?

M = 0.629 M

Explanation:

To calculate the molarity of any solution, you need to use the following expression:

M = n/V (1)

Where:

M: Molarity or concentration of solution (mol/L or M)

n: moles of solute (moles)

V: Volume of solution (In Liters)

But in order to use the above expression, we need to calculate the moles of the HCl, which is calculate with the following expression:

n = m/MM (2)

Where:

m: mass of the HCl (g)

MM: molar mass of HCl (g/mol)

The reported molar mass of HCl is 36.46 g/mol.

Calculating first the moles, using (2) we have:

n = 8.53 / 36.46 = 0.234 moles

Now that we have the moles, we can calculate the molarity, but first we need to pass the volume from mL to Liter:

V = 372 / 1000 = 0.372 L

Finally, let's calculate the molarity using (1) and the value of the obtained moles:

M = 0.234 / 0.372

M = 0.629 M

And this is the molarity of the HCl solution

the electrical  conductivity  of asolution  of an electrolyte is measured by determining the resistance of thesolution  between two flat or cylindrical electrodes separated by a fixed distance.