Answers: 2
(Conjugate base of HF)![pH=pK_{a}\left ( HF \right )+log(\frac{[F^{-}]}{[HF]})](/tpl/images/0247/0730/5ae00.png)
of HF is 3.14![4.05=3.14+log\frac{[F^{-}]}{[HF]}](/tpl/images/0247/0730/971f4.png)
![\Rightarrow \frac{[F^{-}]}{[HF]}=8.13](/tpl/images/0247/0730/c4fbd.png)
![\frac{[NaF]}{[HF]}=8.13](/tpl/images/0247/0730/7d275.png)
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Calculate the ratio of naf to hf required to create a buffer with ph = 4.05....
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