Chemistry
Chemistry, 02.09.2019 16:00, emily200705

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c(s) + o2(g) → co2(g) ∆h = −393.5 kj mol−1
h2(g) + o2(g) → h2o(l) ∆h = −285.8 kj mol−1
3c(s) + 4h2(g) → c3h8(g) ∆h = −104.0 kj mol−1
4c(s) + 5h2(g) → c4h10(g) ∆h = −125.2 kj mol−1
the value in kj mol−1
for the enthalpy of combustion of propane is

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c(s) + o2(g) → co2(g) ∆h = −393.5 kj mol−1

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