In a titration, the endpoint of a neutralization reaction was reached when 37.6 milliliters of an hcl solution was added to 17.3 milliliters of a 0.250 m naoh solution. what was the molarity of the hcl solution?

1) 0.115 m

2) 0.203 m

3) 0.250 m

4)0.543 m

It is important to know first the titration reaction. For this case, it would be,

NaOH + HCl = NaCl + H2O

We are given volumes and concentration we use the relations of moles and volumes to determine the final answer. We do as follows:

(0.250 mol NaOH / L) (.0173 L) ( 1 mol HCl / 1 mol NaOH ) = 0.00433 mol HCl

Concentration = 0.00433 mol HCl / .0376 L = 0.115 M