Chemistry
Chemistry, 02.12.2019 06:31, desirekotta20

The chemical equation below shows the reaction of methane (ch4) and oxygen gas (o2) to form carbon dioxide (co2) and water (h2o). ch4 + 2o2 β†’ co2 + 2h2o in this equation, which of the following are products? oxygen gas and water methane and oxygen gas carbon dioxide and water carbon dioxide and methane

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Answer the questions about this reaction: nai(aq) + cl2(g) β†’ nacl(aq) + i2(g) write the oxidation and reduction half-reactions: oxidation half-reaction: reduction half-reaction: based on the table of relative strengths of oxidizing and reducing agents (b-18), would these reactants form these products? write the balanced equation: answer options: a. 0/na -> +1/na+1e- b. nai(aq) + cl2(g) β†’ nacl(aq) + i2(g) c. +1/na+1e- -> 0 /na d. -1/2i -> 0/i2+2e- e. no f. 4nai(aq) + cl2(g) β†’ 4nacl(aq) + i2(g) g. 2nai(aq) + cl2(g) β†’ 2nacl(aq) + i2(g) h. 4nai(aq) + 2cl2(g) β†’ 4nacl(aq) + 2i2(g) i. nai(aq) + cl2(g) β†’ nacl(aq) + i2(g) j. 0/cl2+2e -> -1/2cl- k. yes
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The chemical equation below shows the reaction of methane (ch4) and oxygen gas (o2) to form carbon d...

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