What volume of a 6.0 m hcl solution is required to make 250.0 milliliters of a 1.5 m hcl?
a.) 0.38 liters
b.) 0.063 liters
c.) 0.25 liters
d.) 1.0 liters
e.) 1.5 liters

The answer is b
M1V1 = M2V2 

where: 
M1 = initial concentration = 6.0 M 
V1 = volume of initial concentration (unknown) 
M2 = final concentration = 1.5 M 
V2 = volume of final concentration = 0.250 L 

(6.0 M)*V1 = (1.5 M)*(0.250 L) 
V1 = 0.063 L