What volume would 3.01•1023 molecules of oxygen gas occupy at stp? 11.2 ml 22.4 ml 11.2 l 22.4 l

Volume  = 11.2 L

Explanation:

Step 1: Calculate Moles:

                     As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.

The relation between Moles, Number of Particles and Avogadro's Number is given as,

                         Number of Moles  =  Number of Particles ÷ 6.022 × 10²³

Putting values,

                         Number of Moles  =  3.01× 10²³ Particles ÷ 6.022 × 10²³

                         Number of Moles  =  0.50 Moles

Step 2: Calculate Volume:

As we know that one mole of any Ideal gas at standard temperature and pressure occupies exactly 22.4 dm³ volume.

When 1 mole gas occupies 22.4 dm³ at STP then the volume occupied by 0.50 moles of gas is calculated as,

                     = (22.4 dm³ × 0.50 moles) ÷ 1 mole

                     = 11.2 dm³                                       ∴ 1dm³ = 1

 Volume  = 11.2 L

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of carbon is as shown here in the image.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.