How many moles of kf are contained in 347 g of water in a 0.175 m kf solution?

347 g of water is the same as 347 ml (since 1 ml of water has a mass of 1 gram). That's 0.347 L.
So the amount of KF is 0.175 * 0.347 = 0.060725 = 6.07 x 10-2

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Both models are effective because they show the valence electrons, and these valence electrons indicate the reactivity of an element.