When a mixture of 12.0 g of acetylene (c2h2 and 12.0 g of oxygen (o2 is ignited, the resultant combustion reaction produces co2 and h2o?

Number of moles of CO₂ formed = 0.375 moles

number of moles of water formed = 0.75 moles

Explanation:

Acetylene reacts with oxygen according to the following chemical reaction:

The molar ratios are :

C₂H₂ = 2

O₂     = 5

CO₂  = 4

H₂O  = 2

The basis is to find a limiting reagent which is given by the lowest number of moles.

The molar mass of acetylene is = 26.04

number of moles of acetylene   =

Number of moles of O₂ =

Number of moles of CO₂ formed = 0.375 moles

number of moles of water formed (2 x 0.375) = 0.75 moles

- lead + phosphoric acid = hydrogen + lead(ii) phosphate