In a reaction where a + b ab, what does an equilibrium position of a= 14%, b = 14%, and ab= 72% indicate about the reaction?

A.) Because A and B are equal, the reaction has reached equilibrium.
B.) There is more A and B than AB at equilibrium, and the reaction favors the reactants.
C.) There is more AB than A and B at equilibrium, and the reaction favors the products.
D.) There is more AB than A and B at equilibrium, and the reaction favors the reactants.
E.) The reaction is not at equilibrium. 
These are the answer choices pls help

The answer is a) carbon-12