Answers: 1
Chemistry, 22.06.2019 14:30, joejoefofana
Consider the reduction reactions and their equilibrium constants. cu+(aq)+eββ½βββcu(s)pb2+(aq)+2eββ½βββ pb(s)fe3+(aq)+3eββ½βββfe(=6.2Γ108=4. 0Γ10β5=9.3Γ10β3 cu + ( aq ) + e β β½ β β β cu ( s ) k =6.2Γ 10 8 pb 2 + ( aq ) +2 e β β½ β β β pb ( s ) k =4.0Γ 10 β 5 fe 3 + ( aq ) +3 e β β½ β β β fe ( s ) k =9.3Γ 10 β 3 arrange these ions from strongest to weakest oxidizing agent.
Answers: 3
Chemistry, 22.06.2019 17:00, emma3216
In a heat engine of 1000 j of heat enters the system and the piston does 500 j of work what is the final internal energy of the system if the inital energy was 2000 j we have to do all of these down here 1)write the equation 2)list out your know variables 3)plug the numbers into the equations 4)solve 5)write your solution statemtn that includes inital energuy and final energuy added
Answers: 1
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