How many grams are in 3.3 moles of potassium sulfide , k2s

In 3.3 moles of potassium sulphide (K2S), there are 363.99 g. Let's first calculate the molar mass of K2S (Mr) which is the sum of atomic masses (Ar) of its elements. According to the periodic table, Ar(K) = 39.1 g/mol and Ar(S) = 32.1 g/mol. Mr(K2S) = 2Ar(K) + Ar(S) = 2 * 39.1 + 32.1 = 110.3 g/mol. Thus, there are 110.3 g per 1 mol. There will be x grams in 3.3 moles. 110.3 g : 1 mol = x : 3.3 mol. x = 110.3 g * 3.3 mol : 1 mol = 363.99 g.

No table found. the question asks for covalent bond based on electronegativies