Chemistry, 09.12.2019 05:31, bnn29

How many molecules of glucose are in 5.72 grams of glucose?

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Each molecule of Glucose has 6 Carbon atoms, 12 Hydrogen atoms and 6 Oxygen atoms
So, the molecular mass of glucose is 6(12) + 12(1.01) + 6(16) = 180.12
If 1 mole of glucose has a mass of 180.12, then let x be the number of moles of glucose that weighs 5.72 grams

180.12(x) = 5.72

So, to get x, we divide 5.72 by 180.12
5.72/180.12 = 0.03 moles

1 mole of any substance has around 6.022 x 10^23 molecules of the atom/molecule/ion

So 0.03 moles has (6.022 x 10^23) x 0.03 = 1.922 x 10^22 molecules

Don't hesitate to ask if you have any questions
Hope I helped xx

answered: bassking1

Glucose is a carbohydrate having chemical formula C₆H₁₂O₆. The molecular mass of glucose is 180.12 grams.

Given that:

The molecular mass of 1 mol of Glucose = 180.12 grams

Given the mass of Glucose = 5.72 grams

Let the a be a number of moles present 5.72 grams, such that:

180.12 $\times$ a = 5.72

a = $\dfrac {5.72}{180.12}$

a = 0.03 moles

Now, from avogadro's constant, we know that:

1 mol = $6.022 \times 10^{23}$

0.03 mol = $6.022 \times 10^{23} \times 0.03$ = $1.922 \times 10^{22}$ molecules

Thus, the number of molecules in the 5.72 grams is $1.922 \times 10^{22}$ molecules.

To know more about moles, refer to the following link:

link

answered: Guest

Ch4 is nonpolar and insoluble in water. since all of the hydrogen atoms are evenly spread around the carbon atom even through the c h bond is polar all the poles cancel each other out.

answered: Guest

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity