For the neutralization reaction involving hno3 and ca(oh)2, how many liters of 1.55 m hno3 are needed to react with 45.8 ml of a 4.66 m ca(oh)2 solution?
1. 0.137 l 2. 0.0343 l 3. 0.275 l 4. 1.32 l 5. 0.662 l 6. 0.330 l

The correct answer is option 3.

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid which is

are the n-factor, molarity and volume of base which is .

We are given:

Putting values in above equation, we get:

1 mL = 0.001 L

Hence, the correct answer is option 3.