100 ml of 1.0 m formic acid (hcooh) is titrated with 1.0 m sodium hydroxide (naoh).
the approximate pka is 4 at the pka, what fraction of the carboxyl group will have been converted to coo-?

Fraction of carboxyl group that will have been converted to COO- = 50%

Explanation:

pKa of formic acid = 4

At pKa, titration is at equivalence point.

At equivalence point, number of moles of HCOOH undissociated is equal to number of moles of dissociated

Thus, fraction of carboxyl group that will have been converted to COO-:

fraction of carboxyl group that will have been converted to COO- = 50%

i think so it’s will be b yes i believe its

it is the most commonly accepted one