What is the empirical formula of a compound that contains 25.92 percent nitrogen and 74.07 percent oxygen?

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of N = 25.92 g

Mass of O = 74.07 g

Step 1 : convert given masses into moles.

Moles of N =

Moles of O =

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For N =

For O =

The ratio of Fe : O= 1:2.5

Converting them into whole numbers, the ratio will be 2: 5

Hence the empirical formula is

answer; i believe that the correct answer is (a) potassium(k)