Iron(iii) oxide is formed when iron combines with oxygen in the air. how many grams of fe2o3 are formed when 25.9 g of fe reacts completely with oxygen? 4fe(s) + 3o2(g) > 2fe2o3(s)

a.12.0g b. 25.0g c. 37.0g d. 49.0g

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

m=9

step-by-step explanation: