Calculate the percent composition of these compounds: (ethane: c2h6) and (sodium hydrogen sulfate: nahso4).

For the first compound,
Molar Mass of C=12.01x 2 =24.02
Molar Mass of H= 1.01x 6= 6.06
So molar mas of C2H6= (12.01x2)+(1.01x6) = 30.08
To get the percent composition, the formula is “(Total MM of C in molecule)/(Total MM of molecule)x 100”.
Here is the solution:
% of C= 24.02/30.08 x 100 = 79.9
% of H=6.06/30.08 x 100=20.1
To check if it is equal to 100%, you just have to add the percentages.
For the second compound,
Molar Mass of Na=22.99 x 1 =22.99
Molar Mass of H= 1.01x 1= 1.01
Molar Mass of S= 32.07x 1= 32.07
Molar Mass of O = 16.00 x4 = 64.00
So molar mas of NaHSO4= (22.99)+(1.01)+(32.07)+(16.00x4) = 120.07
To get the percent composition, the formula is “(Total MM of C in
molecule)/(Total MM of molecule)x 100”.
Here is the solution:
% of Na= 22.99/120.07 x 100 = 19.2
% of H= 1.01/120.07x 100 = 0.8
% of S= 32.07/120.07x 100 = 26.7
% of O= 64/120.07 x 100 = 53.3
To check if it is equal to 100%, you just have to add the percentages.

Just took the quiz on edgenuity and the correct answer is "c.  4.54 x  10–12  j"