Calculate the percent composition of these compounds: (ethane: c2h6) and (sodium hydrogen sulfate: nahso4).

For the first compound,
Molar Mass of C=12.01x 2 =24.02
Molar Mass of H= 1.01x 6= 6.06
So molar mas of C2H6= (12.01x2)+(1.01x6) = 30.08
To get the percent composition, the formula is “(Total MM of C in molecule)/(Total MM of molecule)x 100”.
Here is the solution:
% of C= 24.02/30.08 x 100 = 79.9
% of H=6.06/30.08 x 100=20.1
To check if it is equal to 100%, you just have to add the percentages.
For the second compound,
Molar Mass of Na=22.99 x 1 =22.99
Molar Mass of H= 1.01x 1= 1.01
Molar Mass of S= 32.07x 1= 32.07
Molar Mass of O = 16.00 x4 = 64.00
So molar mas of NaHSO4= (22.99)+(1.01)+(32.07)+(16.00x4) = 120.07
To get the percent composition, the formula is “(Total MM of C in
molecule)/(Total MM of molecule)x 100”.
Here is the solution:
% of Na= 22.99/120.07 x 100 = 19.2
% of H= 1.01/120.07x 100 = 0.8
% of S= 32.07/120.07x 100 = 26.7
% of O= 64/120.07 x 100 = 53.3
To check if it is equal to 100%, you just have to add the percentages.

Answer:

a. energy is absorbed in the reaction.

explanation:

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.