In a famous experiment, wöhler heated ‘inorganic’ ammonium cyanate in the absence of air. the only product of the reaction was ‘organic’ urea, co(nh2)2. no other products were formed in the reaction. what is the formula of the cyanate ion present in ammonium cyanate? a cno– b cno2– c co– d no– why a?
There should be 2 Nitrogen so Cyanate must contain one Nitrogen atom, one Carbon and one oxygen.
considering the question as per the attachment
here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.
when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.
222 = 218 + 4 (atomic mass number)
86 = ? + 2; therefore ? = 86-2 = 84.
the atomic mass number of polonium will be 84.