A12.95 g sample of mo2o3(s) is converted completely to another molybdenum oxide by adding oxygen. the new oxide has a mass of 13.82 g. add subscripts below to correctly identify the empirical formula of the new oxide.

Answer : The empirical formula of the new oxide will be .

Explanation :

First we have to calculate the moles of .

Molar mass of = 240 g/mole

Now we have to calculate the moles of 'Mo'.

As, 1 mole of contains 2 mole 'Mo'

So, 0.0539 mole of contains mole 'Mo'

Now we have to calculate the mass of 'Mo'.

Molar mass of Mo = 95.96 g/mole

Now we have to calculate the mass of oxygen.

Mass of oxygen = 13.82 - 10.34 = 3.48 g

Now we have to calculate the moles of oxygen.

Now we have to calculate the ratio of 'O' and 'Mo'.

Now 3 oxygen are added in , we get the new formula of  oxide.

The new formula of oxide =

Hence, the empirical formula of the new oxide will be .