Using the following equation for the combustion of octane, calculate the amount of grams of carbon dioxide formed from 100.0 g of octane. the molar mass of octane is 114.33 g /mole .the molar mass of carbon dioxide is 44.0095 g/mole.
2 c8h18 +25 o2 > 16 co2 +18 h20
/\h 11018 kj

307.94g of CO₂

Explanation:

Equation of reaction

2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O

molarmass of C₈H₁₈ = 114.33g/mol

2 moles of C₈H₁₈ = 228.66g/mol

Molar mass of CO₂ = 44.0095g/mol

16 moles of CO₂ = 704.152g/mol

From equation of reaction,

2 moles of C₈H₁₈ reacts with 16 moles of CO₂;

228.66g of C₈H₁₈ = 704.152g of CO₂

100g of C₈H₁₈ = y moles of CO₂

y = (100 * 704.152) / 228.66

y = 307.94g of CO₂

Therefore, 100g of C₈H₁₈would yield 307.94g of CO₂.

oh it is true if thats what you are asking

b. accuracy of the data matters alot more than its number of digits, organization or amount of detail. quantitative observation is more accepted than the qualitative observation.