Chemistry
Chemistry, 17.04.2021 07:20, turtle12102

Scientist A produces 83.67 g KMnO4 while Scientist B produces 81.35 g KMnO4 What is the percent yield for Scientist A?
What is the percent yield for Scientist B?
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The equation for the production of potassium permanganate is as follows:
2 MnO2+ 4 KOH + O2-2 KMnO4 + 2 KOH + H2

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Scientist A produces 83.67 g KMnO4 while Scientist B produces 81.35 g KMnO4 What is the percent yie...

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