Scientist A produces 83.67 g KMnO4 while Scientist B produces 81.35 g KMnO4 What is the percent yield for Scientist A?
What is the percent yield for Scientist B?
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The equation for the production of potassium permanganate is as follows:
2 MnO2+ 4 KOH + O2-2 KMnO4 + 2 KOH + H2

Plzz a sample of table sugar (sucrose, c12h22o11) has a mass of 7.801 g. ● a) calculate the number of moles of c12h22o11 in the sample b) calculate the number of moles of each element in c12h22o11 (number of moles of c, number of moles of h & number of moles of o) in the sample. (use your answer from part a as your starting point.) show your work and highlight your final answer. calculate the number of atoms of each element in c12h22o11 (number of atoms of c, number of atoms of h & number of atoms of o) in the sample. (use your answers from part b as your starting for each element.) show your work and highlight your final answer.