4.6 moles of a gas are at a temperature of 325 K and a volume of 96.8 L, what is the pressure of the gas

1.27atm is the pressure of the gas

Explanation:

Using combined gas law, we can find the pressure of a gas with the moles, temperature and volume of the gas. The formula is:

PV = nRT

P = nRT / V

Where P is pressure in atm

n are the moles of the gas: 4.6 moles

R is gas constant: 0.082tamL/molK

T is absolute temperature: 325K

V is volume: 96.8L

Replacing:

P = 4.6mol*0.082atmL/molK*325K / 96.8L

P = 1.27atm is the pressure of the gas

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.