How many moles are present in 5.67x1025 atoms of Carbon (C)?

94 moles of Carbon

Explanation:

From the question,

Using Avogadro's constant

1  mole of every element contains 6.03×10²³ atoms of the element

If 1 mole of Carbon contains 6.03×10²³ atoms of Carbon,

Then, x mole of Carbon will contain 5.67×10²⁵ atoms of Carbon

1 mole of C ⇒ 6.03×10²³ atoms of C

x mole of C ⇒ 5.67×10²⁵ atoms of C

solve for x

x = (1× 5.67×10²⁵)/6.03×10²³

x = 94.03 moles of Carbon

x ≈ 94 moles of Carbon