Aproton moves through a region of space where there is a magnetic field b = (0.45i + 0 38j) t and an electric field e = ( 3.0 i – 4.2 j ) x 10^3 v/m. at a given instant, the proton’s velocity is v = ( 6.0 i + 3.0 j - 5.0 k ) x10^3 m/s . determine the components of the total force on the proton.

At first you have to determine which force influences on the proton. Accorfdng to the task, both electric force and a magnetic force.
So, the following formulae to use : F = Eq 
Fmagnetic=q(v×B). Using these you can calculate vector cross product B (B = (0.45i + 0 38j),  that is hiding in  i and j directions which will interact with k.
Hope it has become clear so that you can solve this task! Regards!

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.