If you want to make 174 grams of NiFz, how many moles of HF will you need, using the following balanced chemical equation? Ni + 2 HF - NiF2 + H2

3.6mol

Explanation:

The balanced chemical equation of this reaction is given as follows:

Ni + 2HF → NiF2 + H2

Based on the above equation, 2 moles of HF will react to produce 1 mole of NiF2.

According to this question, to make 174 grams of NiF2, we find the number of moles of HF required. However, we first convert the mass value of NiF2 to mole value using;

mole = mass/molar mass

Molar mass of NiF2 = 58.7 + 19(2)

= 58.7 + 38

= 96.7g/mol

mole = 174/96.7

mole = 1.799mol of NiF2

Hence, if 2 moles of HF will react to produce 1 mole of NiF2.

- 1.799mol of NiF2 will require (1.799 × 2) = 3.598

= 3.6mol of HF.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24