Determine the volume of the product containing carbon produced when 15.0 g of C2H2 are reacted with an excess of oxygen gas

25.8 L

Explanation:

Step 1: Write the balanced equation for the complete combustion of acetylene

C₂H₂ + 2.5 O₂ ⇒ 2 CO₂ + H₂O

Step 2: Calculate the moles corresponding to 15.0 g of C₂H₂

The molar mass of C₂H₂ is 26.04 g/mol.

15.0 g × 1 mol/26.04 g = 0.576 mol

Step 3: Calculate the moles of CO₂ produced from 0.576 moles of C₂H₂

The molar ratio of C₂H₂ to CO₂ is 1:2. The moles of CO₂ produced are 2/1 × 0.576 mol = 1.15 mol.

Step 4: Calculate the volume corresponding to 1.15 moles of CO₂

At standard temperature and pressure, 1 mole of CO₂ occupies 22.4 L.

1.15 mol × 22.4 L/1 mol = 25.8 L

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.